c語言編寫dh加密演算法程序

Ⅰ 用C語言設計一個文件加密與解密程序

c語言文件加密和解密方法如下：

1、首先打開VC++6.0；

4、聲明頭文件

#include<stdio.h>

#include<stdlib.h>

#include<string.h>

首先寫個加密函數，演算法就是簡介里說的;

voidEncryptFile(FILE*sfp,FILE*dfp,charpwd)
{
charch;
if(sfp==0||dfp==0)
{
printf("ERROR! ");
return;
}
while((ch=fgetc(sfp))!=EOF)
{
if((ch>='a')&&(ch<='z'))
{
ch=(ch-'a'+1)%26+'a';
ch=ch^pwd;
}
if((ch>='A')&&(ch<='Z'))
{
ch=(ch-'A'+1)%26+'A';
ch=ch^pwd;
}
fputc(ch,dfp);
}
}

寫解密子函數：與加密的過程相反;

voidDecryptFile(FILE*sfp,FILE*dfp,charpwd)
{
charch;
while((ch=fgetc(sfp))!=EOF)
{
if((ch>='a')&&(ch<='z'))
{
ch=ch^pwd;
ch=(ch-'a'+25)%26+'a';
}
if((ch>='A')&&(ch<='Z'))
{
ch=ch^pwd;
ch=(ch-'A'+25)%26+'A';
}
fputc(ch,dfp);
}
}

輸出函數，輸出文件內容
voidOutputFile(FILE*fp)
{
charch;
while((ch=fgetc(fp))!=EOF)
putchar(ch);
}
主函數，主要調用這幾個函數
intmain()
{
/*用戶輸入的要加密的文件名*/
charsfilename[20];
/*用戶輸入加密後保存的文件名*/
chardfilename[20];
/*用來保存密碼字元*/
charpwd;
FILE*sfp,*dfp;

printf(": ");
/*得到要加密的文件名*/
gets(sfilename);
/*得到加密後你要的文件名*/
printf(": ");
gets(dfilename);
/*得到加密字元*/
printf("PleaseinputyourPassword: ");
//scanf("%c",&pwd);
pwd=getch();
/*屏幕以*來表示輸入的加密字元*/
printf("* ");
/*以只讀方式打開要加密的文件*/
if((sfp=fopen(sfilename,"r"))==0)
{
printf("Can'topenthefile:%s ",sfilename);
exit(0);
}
/*輸出要加密的文件*/
printf(": ");
OutputFile(sfp);
/*建立加密後的文件*/
if((dfp=fopen(dfilename,"w+"))==0)
{
printf("Can'topenorcreatethefile:%s ",dfilename);
//exit(0);
}
/*文件加密*/
fseek(sfp,0L,SEEK_SET);
EncryptFile(sfp,dfp,pwd);
printf(" Encryptedthefilesuccessfully! ");
/*輸出加密後的文件*/
printf(": ");
fseek(dfp,0L,SEEK_SET);
OutputFile(dfp);
fclose(sfp);
fclose(dfp);
getch();
return0;
}

Ⅱ C語言加密演算法(簡單)

MD5是HASH演算法，他不能用來解密的，他主要是用來校驗信息的完整型，也就是我們常說的數值簽名，你可以去RFC文檔上收索，上邊有他具體的演算法，代碼也是封裝好了的，可以去研究研究

Ⅲ c語言加密演算法

看你催就倉促寫了個，自我感覺寫的不是很好，但是能用了。數據只能是大寫字母組成的字元串。
加密的時候，輸入Y，然後輸入要加密的文本（大寫字母）
解密的時候，輸入N，然後輸入一個整數n表示密文的個數，然後n個整數表示加密時候得到的密文。
/*RSA algorithm */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MM 7081
#define KK 1789
#define PHIM 6912
#define PP 85
typedef char strtype[10000];
int len;
long nume[10000];
int change[126];
char antichange[37];

void initialize()
{ int i;
char c;
for (i = 11, c = 'A'; c <= 'Z'; c ++, i ++)
{ change[c] = i;
antichange[i] = c;
}
}
void changetonum(strtype str)
{ int l = strlen(str), i;
len = 0;
memset(nume, 0, sizeof(nume));
for (i = 0; i < l; i ++)
{ nume[len] = nume[len] * 100 + change[str[i]];
if (i % 2 == 1) len ++;
}
if (i % 2 != 0) len ++;
}
long binamod(long numb, long k)
{ if (k == 0) return 1;
long curr = binamod (numb, k / 2);
if (k % 2 == 0)
return curr * curr % MM;
else return (curr * curr) % MM * numb % MM;
}
long encode(long numb)
{ return binamod(numb, KK);
}
long decode(long numb)
{ return binamod(numb, PP);
}
main()
{ strtype str;
int i, a1, a2;
long curr;
initialize();
puts("Input 'Y' if encoding, otherwise input 'N':");
gets(str);
if (str[0] == 'Y')
{ gets(str);
changetonum(str);
printf("encoded: ");
for (i = 0; i < len; i ++)
{ if (i) putchar('-');
printf(" %ld ", encode(nume[i]));
}
putchar('\n');
}
else
{ scanf("%d", &len);
for (i = 0; i < len; i ++)
{ scanf("%ld", &curr);
curr = decode(curr);
a1 = curr / 100;
a2 = curr % 100;
printf("decoded: ");
if (a1 != 0) putchar(antichange[a1]);
if (a2 != 0) putchar(antichange[a2]);
}
putchar('\n');
}
putchar('\n');
system("PAUSE");
return 0;
}
測試：
輸入：
Y
FERMAT
輸出：
encoded: 5192 - 2604 - 4222
輸入
N
3 5192 2604 4222
輸出
decoded: FERMAT

Ⅳ 用c語言設計一個簡單地加密算，解密演算法，並說明其中的原理

恰巧這兩天剛看的一種思路，很簡單的加密解密演算法，我說一下吧。
演算法原理很簡單，假設你的原密碼是A，用A與數B按位異或後得到C，C就是加密後的密碼，用C再與數B按位異或後能得回A。即（A異或B）異或B=A。用C實現很簡單的。
這就相當於，你用原密碼A和特定數字B產生加密密碼C，別人拿到這個加密的密碼C，如果不知道特定的數字B，他是無法解密得到原密碼A的。
對於密碼是數字的情況可以用下面的代碼：
#include <stdio.h>
#define BIRTHDAY 19880314
int main()
{
long a, b;

scanf("%ld", &a);
printf("原密碼：%ld\n", a);
b = BIRTHDAY;
a ^= b;
printf("加密密碼：%ld\n", a);

a ^= b; printf("解密密碼：%ld\n", a);
return 0;
}
如果密碼是字元串的話，最簡單的加密演算法就是對每個字元重新映射，只要加密解密雙方共同遵守同一個映射規則就行啦。

Ⅳ C語言設計一個簡單的加密解密程序

C語言設計一個簡單的加密解密程序如下：
加密程序代碼：
#include<stdio.h>
main()
{
char c,filename[20];
FILE *fp1,*fp2;
printf("請輸入待加密的文件名:\n");
scanf("%s",filename);
fp1=fopen(filename,"r");
fp2=fopen("miwen.txt","w");
do
{
c=fgetc(fp1);
if(c>=32&&c<=126)
{
c=c-32;
c=126-c;
}
if(c!=-1)
fprintf(fp2,"%c",c);
}
while(c!=-1);
}
解密程序代碼：
#include<stdio.h>
#include<string.h>
main()
{
char c,filename[20];
char yanzhengma[20];
FILE *fp1,*fp2;
printf("請輸入待解密文件名:\n");
scanf("%s",filename);
printf("請輸入驗證碼:\n");
scanf("%s",yanzhengma);
if(strcmp(yanzhengma,"shan")==0)
{
fp1=fopen(filename,"r");
fp2=fopen("yuanwen.txt","w");
do
{
c=fgetc(fp1);
if(c>=32&&c<=126)
{
c=126-c;
c=32+c;
}
if(c!=-1)
fprintf(fp2,"%c",c);
}
while(c!=-1);
}
else
{
printf("驗證碼錯誤！請重新輸入:\n");
scanf("%s",filename);
}
}

Ⅵ 誰知道怎麼用C語言編寫一個加密解密程序.

簡單點的用異或來加解密
例如：
加密 data ^ 因子
解密也很簡單主要講加密後的文本一個一個字元讀取和因子做個異或運算就OK了
復雜的加密解密就參考別的加密演算法吧

Ⅶ c語言編寫加密程序

#include <stdio.h>
#include <string.h>
#include "global.h"
#include "md5.h"

#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21

static void MD5Transform PROTO_LIST ((UINT4 [4], unsigned char
[64]));
static void Encode PROTO_LIST
((unsigned char *, UINT4 *, unsigned int));
static void Decode PROTO_LIST
((UINT4 *, unsigned char *, unsigned int));
static void MD5_memcpy PROTO_LIST ((POINTER, POINTER, unsigned
int));
static void MD5_memset PROTO_LIST ((POINTER, int, unsigned int));

static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};

#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))

#define FF(a, b, c, d, x, s, ac) { (a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b);}
#define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}

void MD5Init (context)
MD5_CTX *context;
{
context->count[0] = context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}

void MD5Update (context, input, inputLen)
MD5_CTX *context;
unsigned char *input;
unsigned int inputLen;
{
unsigned int i, index, partLen;
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
if ((context->count[0] += ((UINT4)inputLen << 3))< ((UINT4)inputLen << 3))
context->count[1]++;
context->count[1] += ((UINT4)inputLen >> 29);
partLen = 64 - index;
if (inputLen >= partLen)
{
MD5_memcpy((POINTER)&context->buffer[index], (POINTER)input, partLen);
MD5Transform (context->state, context->buffer);
for (i = partLen; i + 63 < inputLen; i += 64)
MD5Transform (context->state, &input[i]);
index = 0;
}
else
i = 0;
MD5_memcpy((POINTER)&context->buffer[index], (POINTER)&input[i],inputLen-i);
}

void MD5Final (digest, context)
unsigned char digest[16];
MD5_CTX *context;
{
unsigned char bits[8];
unsigned int index, padLen;
Encode (bits, context->count, 8);
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
MD5Update (context, PADDING, padLen);
MD5Update (context, bits, 8);
Encode (digest, context->state, 16);
MD5_memset ((POINTER)context, 0, sizeof (*context));
}

static void MD5Transform (UINT4 state[4], unsigned char block[64])
{
UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16];
Decode (x, block, 64);
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */

/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */

GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */

/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */

/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */

state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
MD5_memset ((POINTER)x, 0, sizeof (x));
}

static void Encode (output, input, len)
unsigned char *output;
UINT4 *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
{
output[j] = (unsigned char)(input[i] & 0xff);
output[j+1] = (unsigned char)((input[i] >> 8) & 0xff);
output[j+2] = (unsigned char)((input[i] >> 16) & 0xff);
output[j+3] = (unsigned char)((input[i] >> 24) & 0xff);
}
}

static void Decode (output, input, len)
UINT4 *output;
unsigned char *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = ((UINT4)input[j]) | (((UINT4)input[j+1]) << 8) |(((UINT4)input[j+2]) << 16) | (((UINT4)input[j+3]) << 24);
}

static void MD5_memcpy (output, input, len)
POINTER output;
POINTER input;
unsigned int len;
{
unsigned int i;
for (i = 0; i < len; i++)
output[i] = input[i];
}

static void MD5_memset (output, value, len)
POINTER output;
int value;
unsigned int len;
{
unsigned int i;
for (i = 0; i < len; i++)
((char *)output)[i] = (char)value;
}
#ifndef MD
#define MD 5
#endif

#define TEST_BLOCK_LEN 1000
#define TEST_BLOCK_COUNT 1000

static void MDString PROTO_LIST ((char *));
static void MDPrint PROTO_LIST ((unsigned char [16]));

#define MD_CTX MD5_CTX
#define MDInit MD5Init
#define MDUpdate MD5Update
#define MDFinal MD5Final

int main (int argc, char *argv[])
{
int i;
if (argc > 1)
{ MDString(argv[1]);
return (0);
}
}

static void MDString (char *string)
{
MD_CTX context;
unsigned char digest[16];
unsigned int len = strlen (string);

MDInit (&context);
MDUpdate (&context, string, len);
MDFinal (digest, &context);

printf ("MD%d (\"%s\") = ", MD, string);
MDPrint (digest);
printf ("\n");
}

static void MDPrint (unsigned char digest[16])
{
unsigned int i;
for (i = 0; i < 16; i++)
printf ("%02x", digest[i]);

}

Ⅷ c語言加密解密演算法

這里使用的是按位加密，按ASCII碼進行加密的演算法自己寫個，很容易的。
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
void
dofile(char
*in_fname,char
*pwd,char
*out_fname);/*對文件進行加密的具體函數*/
void
usage(char
*name);
void
main(int
argc,char
*argv[])/*定義main()函數的命令行參數*/
{
char
in_fname[30];/*用戶輸入的要加密的文件名*/
char
out_fname[30];
char
pwd[10];/*用來保存密碼*/
if(argc!=4)
{/*容錯處理*/
usage(argv[0]);
printf("\nIn-fname:\n");
gets(in_fname);/*得到要加密的文件名*/
while(*in_fname==NULL)
{
printf("\nIn-fname:\n");
gets(in_fname);
}
printf("Password
6-8:\n");
gets(pwd);/*得到密碼*/
while(*pwd==NULL
||
strlen(pwd)>8
||
strlen(pwd)<6)
{
printf("Password
6-8:\n");
gets(pwd);
}
printf("Out-file:\n");
gets(out_fname);/*得到加密後你要的文件名*/
while(*in_fname==NULL)
{
printf("Out-file:\n");
gets(out_fname);
}
while(!strcmp(in_fname,out_fname))
{
printf("文件名不能和源文件相同\n");
printf("Out-file:\n");
gets(out_fname);
}
dofile(in_fname,pwd,out_fname);
printf("加密成功，解密請再次運行程序\n");
}
else
{/*如果命令行參數正確,便直接運行程序*/
strcpy(in_fname,argv[1]);
strcpy(pwd,argv[2]);
strcpy(out_fname,argv[3]);
while(*pwd==NULL
||
strlen(pwd)>8
||
strlen(pwd)<6)
{
printf("Password
faied!\n");
printf("Password
6-8:\n");
gets(pwd);
}
while(!strcmp(in_fname,out_fname))
{
printf("文件名不能和源文件相同\n");
printf("Out-file:\n");
gets(out_fname);
while(*in_fname==NULL)
{
printf("Out-file:\n");
gets(out_fname);
}
}
dofile(in_fname,pwd,out_fname);
printf("加密成功，解密請再次運行程序\n");
}
}
/*加密子函數開始*/
void
dofile(char
*in_fname,char
*pwd,char
*out_file)
{
FILE
*fp1,*fp2;
register
char
ch;
int
j=0;
int
j0=strlen(pwd);
fp1=fopen(in_fname,"rb");
if(fp1==NULL)
{
printf("cannot
open
in-file.\n");
exit(1);/*如果不能打開要加密的文件,便退出程序*/
}
fp2=fopen(out_file,"wb");
if(fp2==NULL)
{
printf("cannot
open
or
create
out-file.\n");
exit(1);/*如果不能建立加密後的文件,便退出*/
}
/*加密演算法開始*/
while(j0>=0)
{
ch=fgetc(fp1);
while(!feof(fp1))
{
fputc(ch^pwd[j>=j0?j=0:j++],fp2);/*異或後寫入fp2文件*/
ch=fgetc(fp1);
}
j0--;
}
fclose(fp1);/*關閉源文件*/
fclose(fp2);/*關閉目標文件*/
}
void
usage(char
*name)
{
printf("\t=======================File
encryption======================\n");
printf("\tusage:
%s
In-fname
password
out_fname\n",name);
printf("\tExample:
%s
file1.txt
12345678
file2.txt\n",name);
}

Ⅸ 怎樣用C語言編寫簡單加密程序

你就寫個字元數組將字元存進數組，然後將數組的每個元素加4再賦值給自己就行了
例如
char a[3]={'a','b','c'};
for(i=0;i<3;i++)
a[i]+=4;
再輸出數組元素就是加密後的了

謝謝採納

Ⅹ C語言編寫文件加密程序

#include<stdio.h>

charDigitNot(charch){
	charc=0,t;
	inti;
	for(i=0;i<8;++i){
		t=ch&(1<<(7-i));
		if(t)continue;
		c=((c>>(7-i))+1)<<(7-i);
	}
	returnc;
}

char*StrNot(char*sourstr,char*deststr){
	inti;
	for(i=0;sourstr[i];++i)
		deststr[i]=DigitNot(sourstr[i]);
	deststr[i]=0;
	returndeststr;
}

intmain(){
	FILE*infile,*outfile;
	charch,c,str1[]="012aboc靚";
	charstr2[10];
	printf("%s<==>%s
",str1,StrNot(str1,str2));//加密
	printf("%s<==>%s
",str2,StrNot(str2,str1));//解密
	infile=fopen("su","rb");
	outfile=fopen("sum","wb");
	if(infile==NULL||outfile==NULL){
		printf("不能打開文件。
");
		return1;
	}
	while(fread(&ch,1,1,infile)==1){
		c=DigitNot(ch);
		fwrite(&c,1,1,outfile);
	}
	fclose(infile);
	fclose(outfile);
	return0;
}