python排列组合

1. 如何用python列出N个数字的所有排列组合

>> from itertools import combinations, permutations
>> permutations([1, 2, 3], 2)
<itertools.permutations at 0x7febfd880fc0>
# 可迭代对象
>> list(permutations([1, 2, 3], 2)) #排列
[(1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
>> list(combinations([1, 2, 3], 2)) #组合
[(1, 2), (1, 3), (2, 3)]

2. 怎么样让python计算任意六位数的排列组合

from itertools import proct
for i in proct(range(2),repeat=6):
print i

3. 如何在python中列出由一定个数0和1组成的list的排列组合

importitertools
src=[0,0,1]
printset(itertools.permutations(src,len(src)))

这个是正解！

4. Python实现的排列组合计算操作示例

Python实现的排列组合计算操作示例
本文实例讲述了Python实现的排列组合计算操作。分享给大家供大家参考，具体如下：
1. 调用 scipy 计算排列组合的具体数值
>> from scipy.special import comb, perm
>> perm(3, 2)
6.0
>> comb(3, 2)
3.0
2. 调用 itertools 获取排列组合的全部情况数
>> from itertools import combinations, permutations
>> permutations([1, 2, 3], 2)
<itertools.permutations at 0x7febfd880fc0>
# 可迭代对象
>> list(permutations([1, 2, 3], 2))
[(1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
>> list(combinations([1, 2, 3], 2))
[(1, 2), (1, 3), (2, 3)]

5. python 实现6个数的排列组合,每个数可选值为0和1

fromitertoolsimportproct
foriinproct(range(2),repeat=6):
printi

6. python新手问题：排列组合与输出最大数

python2.7语法

第一个问题:

7. Python取随机数排列组合

没懂你的意思，既然是排列组合，就是针对3个固定元素。
如果3个元素本身就是随机的，就不用排列了，下面的getplans函数也就没有意义，直接循环2-5行代码就好。

8. 通过python实现0,1,2,3四个数排列组合可以组成多少个数

##缩进格式看图

import itertools

c=0

for e in itertools.permutations('0123',4):

print(''.join(e).lstrip('0'),end=',')

c+=1

print(' 共%d个'%(c))

9. 在python中如何实现列表中元素的所有排列组合如输入为['1','2','3']和2输出为['

#!/usr/bin/python
#Two method for generate a list whose item is all possible permutation and combination come from every item of many list.

A = ['1', '2']
B = ['a', 'b', 'c']
C = ['A', 'B', 'C', 'D']

retList = []
for a in A:
for b in B:
for c in C:
retList.append((a,b,c))
print retList

print '*' * 40

def myfunc(*lists):
#list all possible composition from many list, each item is a tuple.
#Here lists is [list1, list2, list3], return a list of [(item1,item2,item3),...]

#len of result list and result list.
total = rece(lambda x, y: x * y, map(len, lists))
retList = []

#every item of result list.
for i in range(0, total):
step = total
tempItem = []
for l in lists:
step /= len(l)
tempItem.append(l[i/step % len(l)])
retList.append(tuple(tempItem))

return retList

print myfunc(A,B,C)