Ⅰ java中如何将一个json形式的字符串转为json对象
org.json.jsonobject
去下一个这个jar包吧。
是专用处理json字符串的。
你的这个需求如果对象单一完成可以半自动化完成。
jsonobject
json
=
new
jsonobject(json字符串)
;
if(json.has("你要解析的json是否存在")){
//.....创建你的对象。
//.....解析值并赋值给你的对象
}
如果要实现完成自动解析就得反射了。
以上回答你满意么？
Ⅱ JAVA如何获取json字符串 最好有实例 感谢
//bean类
publicclassTet{
privateStringbuildingNum;//"E1",
privateStringclassName;//"1",
privateStringclassNum;//"通信15-1班",
privateStringcollege;//"电子信息工程学院",
privateStringdormNum;//"110",
privateStringgrade;//"2015",
privateStringisCommunist;//"0",
privateStringisDormLeader;//"1",
privateStringisStudentLeader;//"1",
privateStringmajor;//"通信工程",
privateStringphoneNum;//"13591991111",
privateStringstatus;//"1",
privateStringstudentId;//"1",
privateStringstudentName;//"张三",
privateStringteachername;//"张四"
publicStringgetBuildingNum(){
returnbuildingNum;
}
publicvoidsetBuildingNum(StringbuildingNum){
this.buildingNum=buildingNum;
}
publicStringgetClassName(){
returnclassName;
}
publicvoidsetClassName(StringclassName){
this.className=className;
}
publicStringgetClassNum(){
returnclassNum;
}
publicvoidsetClassNum(StringclassNum){
this.classNum=classNum;
}
publicStringgetCollege(){
returncollege;
}
publicvoidsetCollege(Stringcollege){
this.college=college;
}
publicStringgetDormNum(){
returndormNum;
}
publicvoidsetDormNum(StringdormNum){
this.dormNum=dormNum;
}
publicStringgetGrade(){
returngrade;
}
publicvoidsetGrade(Stringgrade){
this.grade=grade;
}
publicStringgetIsCommunist(){
returnisCommunist;
}
publicvoidsetIsCommunist(StringisCommunist){
this.isCommunist=isCommunist;
}
publicStringgetIsDormLeader(){
returnisDormLeader;
}
publicvoidsetIsDormLeader(StringisDormLeader){
this.isDormLeader=isDormLeader;
}
(){
returnisStudentLeader;
}
publicvoidsetIsStudentLeader(StringisStudentLeader){
this.isStudentLeader=isStudentLeader;
}
publicStringgetMajor(){
returnmajor;
}
publicvoidsetMajor(Stringmajor){
this.major=major;
}
publicStringgetPhoneNum(){
returnphoneNum;
}
publicvoidsetPhoneNum(StringphoneNum){
this.phoneNum=phoneNum;
}
publicStringgetStatus(){
returnstatus;
}
publicvoidsetStatus(Stringstatus){
this.status=status;
}
publicStringgetStudentId(){
returnstudentId;
}
publicvoidsetStudentId(StringstudentId){
this.studentId=studentId;
}
publicStringgetStudentName(){
returnstudentName;
}
publicvoidsetStudentName(StringstudentName){
this.studentName=studentName;
}
publicStringgetTeachername(){
returnteachername;
}
publicvoidsetTeachername(Stringteachername){
this.teachername=teachername;
}
}
//实现类
importnet.sf.json.JSONArray;
publicclassTest{
publicstaticvoidmain(String[]args){
/*
*做法建立一个bean类属性就为字符串的Key;
*/
//定义JSON串String类型
Stringa="[{"buildingNum":"E1","className":"1","classNum":"通信15-1班","college":"电子信息工程学院","dormNum":"110","grade":"2015","isCommunist":"0","isDormLeader":"1","isStudentLeader":"1","major":"通信工程","phoneNum":"13591991111","status":"1","studentId":"1","studentName":"张三","teachername":"张四"},{"buildingNum":"E1","className":"1","classNum":"通信15-1班","college":"电子信息工程学院","dormNum":"110","grade":"2015","isCommunist":"0","isDormLeader":"1","isStudentLeader":"1","major":"通信工程","phoneNum":"13591991111","status":"1","studentId":"2","studentName":"张1","teachername":"张四"},{"buildingNum":"E1","className":"1","classNum":"通信15-1班","college":"电子信息工程学院","dormNum":"110","grade":"2015","isCommunist":"0","isDormLeader":"1","isStudentLeader":"1","major":"通信工程","phoneNum":"13591991111","status":"1","studentId":"3","studentName":"张2","teachername":"张四"},{"buildingNum":"E1","className":"1","classNum":"通信15-1班","college":"电子信息工程学院","dormNum":"101","grade":"2015","isCommunist":"0","isDormLeader":"1","isStudentLeader":"1","major":"通信工程","phoneNum":"13591991111","status":"1","studentId":"4","
+""studentName":"张3","teachername":"张四"}]";
//转换成集合
List<Tet>list2=(List<Tet>)JSONArray.toList(JSONArray.fromObject(a),Tet.class);
for(Tett:list2){
//取出编号
System.out.println(t.getBuildingNum());
}
//转换成数组
Tet[]ss=(Tet[])JSONArray.toArray(JSONArray.fromObject(a),Tet.class);
for(Tett:ss){
//取出姓名
System.out.println(t.getTeachername());
}
}
}
Ⅲ java 怎么把数据json字符串
Java可以使用 fastjson、gson、Jackson或是其他类似的工具将Java对象转成json字符串(同时也可以将json格式转换成java对象)
demo: 将fastjson jar包添加绑定到项目后,需要转换的地方使用如下代码
Useruser=(User)JSONObject.parse(jsonStr);//jsontojava
StringjsonStr=JSONObject.toJSONString(javaObject);//javatojson
Ⅳ JAVA中json字符串如何转化为map对象获取数据
我们需要先把json字符串转化为net.sf.json.JSONObject对象，java中这样就可以完成json字符串到Map的转换了。
Ⅳ Java如何快速构造JSON字符串
用谷歌开发的Gosn包即可，或者自己写
思路：
判断对象类型，Map List 普通bean
分别迭代循环构造（拼接字符串）
利用递归，循环迭代即可。
Ⅵ java 解析json字符串格式 [{}]
你在哪里解析
1、Java类里面：JSONObject jsonObject = new JSONObject(str);
然后用Iterator迭代器遍历取值，建议用反射机制解析到封装好的对象中
2、javascript：JSON.parse(str)；
ie8(兼容模式),ie7和ie6没有JSON对象，不过http://www.json.org/提供了一个json.js,这样ie8(兼容模式),ie7和ie6就可以支持JSON对象以及其stringify()和parse()方法；你可以在https://github.com/douglascrockford/JSON-js上获取到这个js，一般现在用json2.js。
ie8(兼容模式),ie7和ie6可以使用eval()将字符串转为JSON对象，
var c='{"name":"Mike","sex":"女","age":"29"}';
var cToObj=eval("("+str+")");
Ⅶ 关于Java处理JSON字符串的新手问题
Object values=jsonobject.get(keys);这一句写错了，应该是Object values=jsonobject.get(string );不然打印出来是空，你这个json字符串本来就很短，没有规律，不用map中嵌套map，如果嵌套的话不还如写一个实体类把key当时实体类中的属性