a12源碼

Ⅰ 請高手在這個指標中加入一個均線空頭排列的源碼，謝謝。用綠顏色線條和字表示就可。

學習炒股就要去 58L8我發你發 股票學習網去的。

Ⅱ 通達信社保入場公式源碼

社保入場公式
aa:=winner(c+c*15/100)*100;
bb:=winner(c+c*0/100)*100;
cc:=aa-bb;
dd:=(winner(c-c*0.1/100)-winner(c-c*15/100))*100;
ee:=cc<3 and dd<0.5 and o<>l;
a1:=dynainfo(6);
a2:=if(l>a1,0,if(h<a1,1,(a1-l+0.01)/(h-l+0.01)));
a3:=v/winner(l);
a4:=ref(hhv(c,120),1);
a5:=ref(llv(c,120),1);
a6:=100*(c-a5)/(a4-a5);
a7:=a2>0 or a2=1;
a8:=a7 and a3/ref(a3,3)>=3 and a6<80 ;
a9:=ref(a8,1) or ref(a8,2) or ref(a8,3) or ref(a8,4);
a10:=a8 and a9;
a11:=if(filter(a8,3),5,0);
a12:=if(filter(a10,3) or ee,10,0);
進場:a11;
加倉:a12;
社保機構進場日:stickline(a11,0,5,5,0),colorff7700;
社保機構加倉日:stickline(a12,0,15,5,0),colorff00ff;
stickline(a11,0,5,5,0),colorff7700;
stickline(a11,0,5,4.5,0),colorff8800;
stickline(a11,0,5,4,0),colorff9900;
stickline(a11,0,5,3.5,0),colorffaa00;
stickline(a11,0,5,3,0),colorffbb00;
stickline(a11,0,5,2.5,0),colorffcc00;
stickline(a11,0,5,2,0),colorffdd00;
stickline(a11,0,5,1,0),colorffee00;
stickline(a12,0,15,4.5,0),color102099;
stickline(a12,0,15,4,0),color1020aa;
stickline(a12,0,15,3.5,0),color1020bb;
stickline(a12,0,15,3,0),color1020cc;
stickline(a12,0,15,2.5,0),color1020dd;
stickline(a12,0,15,2,0),color1020ee;
stickline(a12,0,15,1,0),color1020ff;
drawtext(a11,8,'進場'),COLORYELLOW;
drawtext(a12,17,'加倉'),COLORWHITE;

股票公式專家團為你解答，希望能幫到你，祝投資順利。

Ⅲ 求C語言將十六進制字元串轉換為整型int的函數源代碼，要求不能用庫函數

/*
請輸入十六進制數 : 120

十 六 進 制 數: 120
十 進 制 數: 288

Press any key to continue
*/
#include <ctype.h>
#include <stdio.h>
#define MAX 10
#define NewLine 10
main () {
char num16[MAX];
unsigned long cocnvertfactor = 1,num10 = 0;
char ch,j,i = 0;
printf("請輸入十六進制數 : ");
while (((ch = getchar()) != NewLine) && (i < MAX))
if ((ch >= '0' && ch <= '9') || (ch >= 'A' && ch <= 'F') || (ch >= 'a' && ch <= 'f'))
num16[i++] = ch; // 僅接收數字和英文前6個字母
for (j = 0;j < i;j++) num16[j] = toupper(num16[j]); // 小寫字母轉換成大寫，其他字元不變
for (j = i - 1;j >= 0;j--) { // 開始轉換
if (isalpha(num16[j])) num10 = num10 + cocnvertfactor*(num16[j] - 'A' + 10);
else num10 = num10 + cocnvertfactor*(num16[j] - '0');
cocnvertfactor = 16*cocnvertfactor;
}
printf("\n十 六 進 制 數: ");
for (j = 0;j < i;j++) printf("%c",num16[j]);
printf("\n十 進 制 數: %u\n\n\n",num10);
}

Ⅳ 一隻桶里有12升油，要求平均分為兩份，現有9升和5升兩個空桶，用C語言遞歸解決，最好寫出源代碼，謝謝

#include<stdio.h>

unsignedshorttemp[20];//存儲中間狀態

intstep=0;//

charOP[][16]={

"初始狀態",

"A全倒給B",

"A全倒給C",

"A倒滿B",

"A倒滿C",

"B全倒給A",

"B全倒給C",

"B倒滿C",

"C全倒給A",

"C全倒給B",

"C倒滿B"

};

//輸出步驟

voiddisplay()

{

inti;

for(i=0;i<=step;i++)

printf("%2d:[%10s]:%d,%d,%d ",

i+1,

OP[(temp[i]&0xf000)>>12],

(temp[i]&0xf00)>>8,

(temp[i]&0xf0)>>4,

temp[i]&0xf);

}

//檢查是否會出現重復狀態

intcheck()

{

inti;

for(i=0;i<step;i++)

{

if((temp[step]&0x0fff)==(temp[i]&0x0fff))return1;

}

return0;

}

//遞歸函數

//A,B,C分別是3個油桶當前有多少油，op是倒油的具體操作

intfoo(intA12,intB9,intC5,intop)

{

temp[step]=(op<<12)|(A12<<8)|(B9<<4)|C5;

if(check()==1)return0;

if(A12==6&&B9==6)return1;

step++;

//A12全部倒給B9

if(A12&&(A12+B9<=9)&&foo(0,A12+B9,C5,1))return1;

//A12全部倒給C5

elseif(A12&&(A12+C5<=5)&&foo(0,B9,A12+C5,2))return1;

//A12倒滿B9

elseif(A12&&(A12+B9>9)&& foo(A12+B9-9,9,C5,3))return1;

//A12倒滿C5

elseif(A12&&(A12+C5>5)&&foo(A12+C5-5,B9,5,4))return1;

//B9全部倒給A12

elseif(B9&&(B9+A12<12)&&foo(A12+B9,0,C5,5))return1;

//B9全部倒給C5

elseif(B9&&(B9+C5<=5)&&foo(A12,0,B9+C5,6))return1;

//B9倒滿C5

elseif(B9&&(B9+C5>5)&&foo(A12,B9+C5-5,5,7))return1;

//C5全部倒給A12

elseif(C5&&(C5+A12<12)&&foo(C5+A12,B9,0,8))return1;

//C5全部倒給B9

elseif(C5&&(C5+B9<=9)&&foo(A12,B9+C5,0,9))return1;

//C5倒滿B9

elseif(C5&&(C5+B9>9)&&foo(A12,9,C5+B9-5,10))return1;

else

{

step--;

return0;

}

}

intmain()

{

if(foo(12,0,0,0))display();

}

結果：

Ⅳ 求利用動態規劃求矩陣相乘的最少次數的源代碼感激不盡啊~~

//STRASSEN矩陣乘法演算法

#include <iostream.h>

const int N=8; //常量N用來定義矩陣的大小

void main()
{

void STRASSEN(int n,float A[][N],float B[][N],float C[][N]);
void input(int n,float p[][N]);
void output(int n,float C[][N]); //函數聲明部分

float A[N][N],B[N][N],C[N][N]; //定義三個矩陣A,B,C

cout<<"現在錄入矩陣A[N][N]:"<<endl<<endl;
input(N,A);
cout<<endl<<"現在錄入矩陣B[N][N]:"<<endl<<endl;
input(N,B); //錄入數組

STRASSEN(N,A,B,C); //調用STRASSEN函數計算

output(N,C); //輸出計算結果
}

void input(int n,float p[][N]) //矩陣輸入函數
{
int i,j;

for(i=0;i<n;i++)
{
cout<<"請輸入第"<<i+1<<"行"<<endl;
for(j=0;j<n;j++)
cin>>p[i][j];
}
}

void output(int n,float C[][N]) //據矩陣輸出函數
{
int i,j;
cout<<"輸出矩陣:"<<endl;
for(i=0;i<n;i++)
{
cout<<endl;
for(j=0;j<n;j++)
cout<<C[i][j]<<" ";
}
cout<<endl<<endl;

}

void MATRIX_MULTIPLY(float A[][N],float B[][N],float C[][N]) //按通常的矩陣乘法計算C=AB的子演算法(僅做2階)
{
int i,j,t;
for(i=0;i<2;i++) //計算A*B-->C
for(j=0;j<2;j++)
{
C[i][j]=0; //計算完一個C[i][j]，C[i][j]應重新賦值為零
for(t=0;t<2;t++)
C[i][j]=C[i][j]+A[i][t]*B[t][j];
}
}

void MATRIX_ADD(int n,float X[][N],float Y[][N],float Z[][N]) //矩陣加法函數X+Y—>Z
{
int i,j;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
Z[i][j]=X[i][j]+Y[i][j];
}

void MATRIX_SUB(int n,float X[][N],float Y[][N],float Z[][N]) //矩陣減法函數X-Y—>Z
{
int i,j;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
Z[i][j]=X[i][j]-Y[i][j];

}

void STRASSEN(int n,float A[][N],float B[][N],float C[][N]) //STRASSEN函數（遞歸）
{
float A11[N][N],A12[N][N],A21[N][N],A22[N][N];
float B11[N][N],B12[N][N],B21[N][N],B22[N][N];
float C11[N][N],C12[N][N],C21[N][N],C22[N][N];
float M1[N][N],M2[N][N],M3[N][N],M4[N][N],M5[N][N],M6[N][N],M7[N][N];
float AA[N][N],BB[N][N],MM1[N][N],MM2[N][N];

int i,j;//,x;

if (n==2)
MATRIX_MULTIPLY(A,B,C);//按通常的矩陣乘法計算C=AB的子演算法(僅做2階)
else
{
for(i=0;i<n/2;i++) //////////
for(j=0;j<n/2;j++)

{
A11[i][j]=A[i][j];
A12[i][j]=A[i][j+n/2];
A21[i][j]=A[i+n/2][j];
A22[i][j]=A[i+n/2][j+n/2];
B11[i][j]=B[i][j];
B12[i][j]=B[i][j+n/2];
B21[i][j]=B[i+n/2][j];
B22[i][j]=B[i+n/2][j+n/2];
} //將矩陣A和B式分為四塊

MATRIX_SUB(n/2,B12,B22,BB); //////////
STRASSEN(n/2,A11,BB,M1);//M1=A11(B12-B22)

MATRIX_ADD(n/2,A11,A12,AA);
STRASSEN(n/2,AA,B22,M2);//M2=(A11+A12)B22

MATRIX_ADD(n/2,A21,A22,AA);
STRASSEN(n/2,AA,B11,M3);//M3=(A21+A22)B11

MATRIX_SUB(n/2,B21,B11,BB);
STRASSEN(n/2,A22,BB,M4);//M4=A22(B21-B11)

MATRIX_ADD(n/2,A11,A22,AA);
MATRIX_ADD(n/2,B11,B22,BB);
STRASSEN(n/2,AA,BB,M5);//M5=(A11+A22)(B11+B22)

MATRIX_SUB(n/2,A12,A22,AA);
MATRIX_SUB(n/2,B21,B22,BB);
STRASSEN(n/2,AA,BB,M6);//M6=(A12-A22)(B21+B22)

MATRIX_SUB(n/2,A11,A21,AA);
MATRIX_SUB(n/2,B11,B12,BB);
STRASSEN(n/2,AA,BB,M7);//M7=(A11-A21)(B11+B12)
//計算M1,M2,M3,M4,M5,M6,M7（遞歸部分）

MATRIX_ADD(N/2,M5,M4,MM1); ////////////
MATRIX_SUB(N/2,M2,M6,MM2);
MATRIX_SUB(N/2,MM1,MM2,C11);//C11=M5+M4-M2+M6

MATRIX_ADD(N/2,M1,M2,C12);//C12=M1+M2

MATRIX_ADD(N/2,M3,M4,C21);//C21=M3+M4

MATRIX_ADD(N/2,M5,M1,MM1);
MATRIX_ADD(N/2,M3,M7,MM2);
MATRIX_SUB(N/2,MM1,MM2,C22);//C22=M5+M1-M3-M7

for(i=0;i<n/2;i++)
for(j=0;j<n/2;j++)
{
C[i][j]=C11[i][j];
C[i][j+n/2]=C12[i][j];
C[i+n/2][j]=C21[i][j];
C[i+n/2][j+n/2]=C22[i][j];
} //計算結果送回C[N][N]

}

}

Ⅵ 通達信根據指標源碼怎樣編選股公式

VAR3:=(CLOSE-MA(CLOSE,6))/MA(CLOSE,6)*100;
VAR4:=(CLOSE-MA(CLOSE,24))/MA(CLOSE,24)*100;
VAR5:=(CLOSE-MA(CLOSE,32))/MA(CLOSE,32)*100;
VAR6:=(VAR3+VAR4+VAR5)/3;
VAR7:=EMA(VAR6,5);
ZB:=EMA(EMA(VAR3,5),5)*3;
VAR8:=IF(VAR6<=-20,10,0);
VAR9:=HHV(VAR8,10);
VARA:=IF(VAR9 AND CROSS(MA(CLOSE,3),MA(CLOSE,5)),20,0);
准備:=VAR8=10 AND FILTER(VAR8=10,5);
一定要買:=VARA=20;
VARF:=100-3*SMA((CLOSE-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1)+2*SMA(SMA((CLOSE-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1),15,1);
VAR10:=100-3*SMA((OPEN-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1)+2*SMA(SMA((OPEN-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1),15,1);
VAR11:=VARF<REF(VAR10,1) AND VOL>REF(VOL,1) AND CLOSE>REF(CLOSE,1);
莊家異動:=VAR11 AND COUNT(VAR11,30)=1;
錢包:=(ZIG(3,5)>REF(ZIG(3,5),1)) AND (REF(ZIG(3,5),1)<=REF(ZIG(3,5),2)) AND (REF(ZIG(3,5),2)<=REF(ZIG(3,5),3));
XG:(准備 OR 一定要買 OR 莊家異動) AND 錢包;

=======================
{單獨出現}
VAR3:=(CLOSE-MA(CLOSE,6))/MA(CLOSE,6)*100;
VAR4:=(CLOSE-MA(CLOSE,24))/MA(CLOSE,24)*100;
VAR5:=(CLOSE-MA(CLOSE,32))/MA(CLOSE,32)*100;
VAR6:=(VAR3+VAR4+VAR5)/3;
VAR7:=EMA(VAR6,5);
ZB:=EMA(EMA(VAR3,5),5)*3;
VAR8:=IF(VAR6<=-20,10,0);
VAR9:=HHV(VAR8,10);
VARA:=IF(VAR9 AND CROSS(MA(CLOSE,3),MA(CLOSE,5)),20,0);
准備:=VAR8=10 AND FILTER(VAR8=10,5);
一定要買:=VARA=20;
VARF:=100-3*SMA((CLOSE-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1)+2*SMA(SMA((CLOSE-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1),15,1);
VAR10:=100-3*SMA((OPEN-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1)+2*SMA(SMA((OPEN-LLV(LOW,75))/(HHV(HIGH,75)-LLV(LOW,75))*100,20,1),15,1);
VAR11:=VARF<REF(VAR10,1) AND VOL>REF(VOL,1) AND CLOSE>REF(CLOSE,1);
莊家異動:=VAR11 AND COUNT(VAR11,30)=1;
錢包:=(ZIG(3,5)>REF(ZIG(3,5),1)) AND (REF(ZIG(3,5),1)<=REF(ZIG(3,5),2)) AND (REF(ZIG(3,5),2)<=REF(ZIG(3,5),3));
XG:准備 OR 一定要買 OR 莊家異動 OR 錢包;

Ⅶ 新版同花順指標公式修改時總是彈出"重要提示"，怎麼辦

同花順編公式時總是提示缺少是因為方法有問題，請參考下面：
1、打開同花順軟體，點擊 工具
2、點擊 工具 後，會出現下拉菜單，點擊 公式管理
3、點擊 公式管理 後，會出現公式管理界面，選中 技術指標 後，點擊 新建
4、點擊 新建 後，會出現對話框，選中 技術指標 後，點擊 確定。(如果你的是 條件選股公式源碼 ，則選擇 條件選股 再點擊 確定 )
5、點擊 確定 後，會出現公式編輯框，在最上方的 名稱 欄填入公式名稱，注意公式名稱必須是英文字元，然後再 描述 欄中填入公式描述，再將公式源碼粘貼到下面的公式源碼編輯框6、上述步驟完成之後，點擊 測試公式 ，若公式源碼沒有問題，會提示編譯測試成功！
7、公式源碼編譯成功之後，點擊 確定
8、點擊 確定 後 ，會彈出如下確認框，再次點擊 確定 ，公式就已經導入到軟體了。
9、公式導入之後，如何調出這個公式來使用呢？很簡單，只需要使用鍵盤精靈即可，比如導入的是一個 通達信 的公式指標，公式名稱設置的是TDX，那麼要使用的話就只需要用鍵盤輸入 TDX 即可顯示所導入的公式。
10、選中 通達信 公式指標即可。公式指標欄目將會出現相應的指標圖。

那麼根據公式源碼進行輸入，就可以解決這個條件缺少的問題了。
0,COLOR666666;
DIF1:=(EMA(C,6)-EMA(C,13));
DEA1:=EMA(DIF1,6),colorwhite;
MACD1:=(DIF1-DEA1)*2;
MAMACD1:=MA(MACD1,2);
DIF2:=(EMA(C,12)-EMA(C,26));
DEA2:=EMA(DIF2,9),colorwhite;
MACD2:=(DIF2-DEA2)*2;
MAMACD2:=MA(MACD2,2);
DIF3:=(EMA(C,20)-EMA(C,60));
DEA3:=EMA(DIF3,10),colorwhite;
MACD3:=(DIF3-DEA3)*2;
MAMACD3:=MA(MACD3,2);
DIF4:=(EMA(C,60)-EMA(C,120));
DEA4:=EMA(DIF4,10),colorwhite;
MACD4:=(DIF4-DEA4)*2;
MAMACD4:=MA(MACD4,2);
DIF5:=(EMA(C,120)-EMA(C,250));
DEA5:=EMA(DIF5,10),colorwhite;
MACD5:=(DIF5-DEA5)*2;
MAMACD5:=MA(MACD5,2);
DIF6:=(EMA(C,250)-EMA(C,500));
DEA6:=EMA(DIF6,10),colorwhite;
MACD6:=(DIF6-DEA6)*2;
MAMACD6:=MA(MACD6,2);
A1:=DIF1>=REF(DIF1,1);
A2:=DIF2>=REF(DIF2,1);
A3:=DIF3>=REF(DIF3,1);
A4:=DIF4>=REF(DIF4,1);
A5:=DIF5>=REF(DIF5,1);
A6:=DIF6>=REF(DIF6,1);
B1:=DIF1<=REF(DIF1,1);
B2:=DIF2<=REF(DIF2,1);
B3:=DIF3<=REF(DIF3,1);
B4:=DIF4<=REF(DIF4,1);
B5:=DIF5<=REF(DIF5,1);
B6:=DIF6<=REF(DIF6,1);
A7:=DIF6>0 AND DIF6<REF(DIF6,1);//{熊市初期}
A8:=DIF6<0 AND DIF6>REF(DIF6,1);//{牛市初期}
A9:=DIF6<0 AND DIF6<REF(DIF6,1);//{熊市中後期}
A10:=DIF6>0 AND DIF6>REF(DIF6,1);//{牛市成長期}
A11:=DIF4<=REF(DIF4,1);
A12:=DIF5<=REF(DIF5,1);
STICKLINE(A6,0,1,3,0),colorblue;
STICKLINE(A5,1,2,3,0),COLORDDDDDD;
STICKLINE(A4,2,3,3,0),colorred;
STICKLINE(A4 AND A3 AND A2,3,4,3,0),colormagenta;
STICKLINE(A4 AND A3 AND A2 AND A1,4,5,3,0),coloryellow;
STICKLINE(B6,0,1,3,0),COLOR333333;
STICKLINE(B5,1,2,3,0),COLOR444444;
STICKLINE(B4,2,3,3,0),COLOR666666;
STICKLINE(A6 OR A5,7.5,8,3,0),COLOR339999;
STICKLINE(A6 OR A5,7.5,8,1,0),COLOR33FFFF;
STICKLINE(B5 OR B6,7.5,8,3,0),COLOR333333;
STICKLINE(B5 OR B6,7.5,8,1,0),COLOR666666;
STICKLINE((A6 OR A5) AND A4 AND A3 AND A2 ,7.5,8,3,0),COLOR993399;
STICKLINE((A6 OR A5) AND A4 AND A3 AND A2 ,7.5,8,1,0),COLORFF00FF;
STICKLINE((B6 OR B5) AND A4 AND A3 AND A2 AND A1,7.5,8,3,0),COLOR666600;
STICKLINE((B6 OR B5) AND A4 AND A3 AND A2 AND A1,7.5,8,1,0),COLORFFFF00;
整體已經全部測試通過，放心使用。

Ⅷ 請幫忙把兩點一線+通道的指標公式改成通達信

LC:=REF(CLOSE,1);
B1:SMA(MAX(CLOSE-LC,0),4,1)/SMA(ABS(CLOSE-LC),4,1)*100-34,NODRAW;
A1:STICKLINE(CLOSE>=OPEN AND B1<34,CLOSE,OPEN,5,0),COLORCYAN;
A2:STICKLINE(CLOSE>=OPEN AND B1<34,HIGH,CLOSE,0,0),COLORCYAN;
A3:STICKLINE(CLOSE>=OPEN AND B1<34,OPEN,LOW,0,0),COLORCYAN;
A4:STICKLINE(CLOSE<OPEN AND B1<34,CLOSE,OPEN,5,0),COLORCYAN;
A5:STICKLINE(CLOSE<OPEN AND B1<34,HIGH,OPEN,0,0),COLORCYAN;
A6:STICKLINE(CLOSE<OPEN AND B1<34,LOW,CLOSE,0,0),COLORCYAN;
VAR0:=(CLOSE-LLV(LOW,32))/(HHV(HIGH,32)-LLV(LOW,32))*CLOSE;
VAR1:=EMA(VAR0,3);
VAR3:=EMA(VAR0,7);
HH:=HHV(VAR3,64);
LL:=LLV(VAR3,64);
VARHIGH:=IF(VAR1>=REF(HH,1),H,REF(H,BARSLAST(VAR1>=REF(HH,1))));
VARLOW:=IF(VAR1<=REF(LL,1),L,REF(L,BARSLAST(VAR1<=REF(LL,1))));
B5:PLOYLINE(VARHIGH=REF(VARHIGH,1),VARHIGH),COLORRED;
B2:PLOYLINE(VARLOW=REF(VARLOW,1),VARLOW),COLORGREEN;
B3:MA(C,21);
RSV:(HHV(HIGH,14)-CLOSE)/(HHV(HIGH,14)-LLV(LOW,14))*100,NODRAW;
A7:STICKLINE(CLOSE>=OPEN AND RSV<35,CLOSE,OPEN,5,1),COLORRED;
A8:STICKLINE(CLOSE>=OPEN AND RSV<35,HIGH,CLOSE,0,0),COLORRED;
A9:STICKLINE(CLOSE>=OPEN AND RSV<35,OPEN,LOW,0,0),COLORRED;
A10:STICKLINE(CLOSE<OPEN AND RSV<35,CLOSE,OPEN,5,1),COLORRED;
A11:STICKLINE(CLOSE<OPEN AND RSV<35,HIGH,OPEN,0,0),COLORRED;
A12:STICKLINE(CLOSE<OPEN AND RSV<35,LOW,CLOSE,0,0),COLORRED;
中軌:MA(CLOSE,10),COLORWHITE;
上軌:中軌+2*STD(CLOSE,10),COLORWHITE;
下軌:中軌-2*STD(CLOSE,10),COLORWHITE;
A13:STICKLINE(CLOSE>=OPEN AND CROSS(CLOSE,上軌) AND CLOSE/OPEN>1.09,CLOSE,OPEN,10,0);
A14:STICKLINE(CLOSE>=OPEN AND CROSS(CLOSE,上軌) AND CLOSE/OPEN>1.09,HIGH,CLOSE,0,0);
A15:STICKLINE(CLOSE>=OPEN AND CROSS(CLOSE,上軌) AND CLOSE/OPEN>1.09,OPEN,LOW,0,0);
A16:STICKLINE(CLOSE<OPEN AND CROSS(CLOSE,上軌) AND CLOSE/OPEN>1.09,CLOSE,OPEN,10,0);
A17:STICKLINE(CLOSE<OPEN AND CROSS(CLOSE,上軌) AND CLOSE/OPEN>1.09,HIGH,OPEN,0,0);
A18:STICKLINE(CLOSE<OPEN AND CROSS(CLOSE,上軌) AND CLOSE/OPEN>1.09,LOW,CLOSE,0,0);
{公式好象有點問題,通達信可能用了,但有時會缺少K線,不知道你這公式源碼全不全}