python判断ip段

⑴ python 判断是ipv6还是ipv4 inet

ipv4与ipv6地址如何转换的python解决办法

ipv4与ipv6地址如何转换的python解决办法。要想知道ipv4与ipv6地址转换的问题，首先要了解它的概念。

ipv4与ipv6地址是什么简单的来说一下：
IPv4：是互联网协议的第四版,同时也是第一个被广泛使用，构成现今互联网技术的基石的协议；
IPv6：是互联网工程任务组设计的用于替代现行版本IPv4的下一代IP协议；
目前IP协议的版本号是IPv4，它的下一个版本就是IPv6。

ipv4与ipv6地址如何转换的python解决办法，源码如下：（需要用到twisted.python.compat及struct和python socket方法）

import struct,socket
#import twisted.python.compat #导入twisted.python.compat 更方便

# ipv4数字地址
def ipv4_to_string(ipv4):
ipv4_n = socket.htonl(ipv4)
data = struct.pack('I', ipv4_n)
ipv4_string = socket.inet_ntop(socket.AF_INET, data)
return ipv4_string

def ipv4_from_string(ipv4_string):
data = socket.inet_pton(socket.AF_INET, ipv4_string)
ipv4_n = struct.unpack('I', data)
ipv4 = socket.ntohl(ipv4_n[0])
return ipv4

def ipv4_readable2int(ipv4):
return int(ipv4)

def ipv4_int2readable(ipv4):
return str(ipv4)

# ipv6用四个整数(tuple或用,分开的字符串)表示
def ipv6_to_string(ipv6):
ipv6_n = (socket.htonl(ipv6[0]),
socket.htonl(ipv6[1]),
socket.htonl(ipv6[2]),
socket.htonl(ipv6[3]))
data = struct.pack('IIII', ipv6_n[0], ipv6_n[1], ipv6_n[2], ipv6_n[3])
ipv6_string = socket.inet_ntop(socket.AF_INET6, data)

return ipv6_string

def ipv6_from_string(ipv6_string):
data = socket.inet_pton(socket.AF_INET6, ipv6_string)
ipv6_n = struct.unpack('IIII', data)
ipv6 = (socket.ntohl(ipv6_n[0]),
socket.ntohl(ipv6_n[1]),
socket.ntohl(ipv6_n[2]),
socket.ntohl(ipv6_n[3]))

return ipv6

def ipv6_tuple2readable(ipv6):
return str(ipv6[0]) + ',' + str(ipv6[1]) + ',' + str(ipv6[2]) + ',' + str(ipv6[3])

def ipv6_readable2tuple(ipv6):
return tuple(ipv6.split(','))

#win32 下实现 inet_pton 和 inet_ntop
def inet_ntop(family, ipstr):
if family== socket.AF_INET:
return socket.inet_ntoa(ipstr)
elif family== socket.AF_INET6:
v6addr = ':'.join(('%02X%02X' % (ord(i), ord(j)))
for i,j in zip(ipstr[::2], ipstr[1::2]))
return v6addr

#www.iplaypy.com

def inet_pton(family, addr):
if family== socket.AF_INET:
return socket.inet_aton(addr)

elif family== socket.AF_INET6:
if '.' in addr: # a v4 addr
v4addr = addr[addr.rindex(':')+1:]
v4addr = socket.inet_aton(v4addr)
v4addr = map(lambda x: ('%02X' % ord(x)), v4addr)
v4addr.insert(2, ':')
newaddr = addr[:addr.rindex(':')+1] + ''.join(v4addr)
return inet_pton(family, newaddr)
dbyts = [0]* 8 # 8 groups
grps = addr.split(':')

for i,v in enumerate(grps):
if v:
dbyts[i] = int(v, 16)
else:
for j, w in enumerate(grps[::-1]):
if w:
dbyts[7-j] = int(w, 16)
else:
break
break
return ''.join( (chr(i//256) + chr(i%256)) for i in dbyts)

else:
raise RuntimeError("What family?")

⑵ python判断IP地址合法性程序题有个小问题求助！！

if count == 4:
print('yes')

else: #这里需要对应一个else
print('no')