A. 在java中,如何检测一个数组中是否包含某一个数据
在Java中,检测一个数组是否包含某一个数据,通常有四种方法:
(1)for循环
(2)转换为List,调用Arrays.asList(arr).contains方法
(3)使用Set
(4)使用Arrays.binarySearch()方法
下面为上述四种方法的具体代码实现:
1、使用for循环
publicstaticbooleanuseLoop(String[]arr,StringtargetValue){
for(Strings:arr){
if(s.equals(targetValue))
returntrue;
}
returnfalse;
}
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2、转换为List,调用Arrays.asList(arr).contains方法
publicstaticbooleanuseList(String[]arr,StringtargetValue){
returnArrays.asList(arr).contains(targetValue);
}
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3、使用Set
publicstaticbooleanuseSet(String[]arr,StringtargetValue){
SetStringset=newHashSetString(Arrays.asList(arr));
returnset.contains(targetValue);
}
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4、使用Arrays.binarySearch()方法
特别说明:binarySearch()二分查找仅适用于有序数组,如果不是有序数组,则报异常
(String[]arr,StringtargetValue){
inta=Arrays.binarySearch(arr,targetValue);
if(a0){
returntrue;
}else{
returnfalse;
}}
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(1)javasetstring扩展阅读:
Java种List列表的contains方法:
该方法是通过遍历集合中的每一个元素并用equals方法比较是否存在指定的元素。
publicbooleancontains(Objecto){
IteratorEit=iterator();
if(o==null){
while(it.hasNext())
if(it.next()==null)
returntrue;
}else{
while(it.hasNext())
if(o.equals(it.next()))
returntrue;
}
returnfalse;
}
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B. JAVA 找不到符号
public void setStirng(String mystring)
{
this.s = mystring();
}
SETSTRING的语句块出现问题了撒。你传的参数是一个字符串,怎么会在使用的时候改成了函数了呢。mystring()的这种调用方式是一个以函数来进行调用的方式的。不能这样写的。。。
你如果想获得mstring的话,那么你就直接写this.s = mystring就可以了撒。干嘛非要加个括号呢。
要是你真想加个括号的话也不是不可以的。你再写一个mystring的函数就可以了 的。然后在里面进行一些操作也是可以的。。