① java解析json字符串 放到数组中
java解析json字符串时将大括号中的对应为一个类,里面的数据对应为类的属性,最后用数组接受即可。
示例关键代码如下:
//导入net.sf.json.JSONArray和net.sf.json.JSONObject两个jar包
Stringstr="[{name:'a',value:'aa'},{name:'b',value:'bb'},{name:'c',value:'cc'},{name:'d',value:'dd'}]";//一个未转化的字符串
JSONArrayjson=JSONArray.fromObject(str);//首先把字符串转成JSONArray对象
if(json.size()>0){
for(inti=0;i<json.size();i++){
JSONObjectjob=json.getJSONObject(i);//遍历jsonarray数组,把每一个对象转成json对象
System.out.println(job.get("name")+"=");//得到每个对象中的属性值
}
}
② 请教JAVA中的JSON字符串转数组的问题
使用com.alibaba.fastjson这个jar包,调用里面的JSON.parseArray方法进行转换
③ java中怎么把json转换成对象数组
1、使用原生的解析:
String json = "...";
JSONArray array= new JSONArray(json);
//遍历数组里的值,得到每个独立的对象,然后获取对应的值设置到声明好的对象中,最终创建对象完成后添加到集合中,如我自己代码里的片段:
for (int j = 0; j < array.length(); j++) {
obj = array.getJSONObject(j);
Data data = new Data();
data.setThumbnail(obj.getString("thumbnail"));
data.setTitle(obj.getString("title"));
data.setUrl(obj.getString("url"));
mDataList.add(data);
}
2、使用第三方包如Gson,但是这个你得保证你的JSON字符串个z
④ java中把json怎么转换成数组
java中把json怎么转换成数组的方法:
1、使用原生的解析:
String json = "...";
JSONArray array= new JSONArray(json);
//遍历数组里的值,得到每个独立的对象,然后获取对应的值设置到声明好的对象中,最终创建对象完成后添加到集合中,如我自己代码里的片段:
for (int j = 0; j < array.length(); j++) {
obj = array.getJSONObject(j);
Data data = new Data();
data.setThumbnail(obj.getString("thumbnail"));
data.setTitle(obj.getString("title"));
data.setUrl(obj.getString("url"));
mDataList.add(data);
}
2、使用第三方包如Gson,但是这个你得保证你的JSON字符串个z
⑤ 怎么把 json 格式转换成 数组格式
varobj={"pieTes":[{"colors":"Sony","value":7},{"colors":"Samsumg","value":14},{"colors":"LG","value":21},{"colors":"Vizio","value":34},{"colors":"Insignia","value":24}]};
vararr=newArray();
for(variinx.pieTes){
arr.push([x.pieTes[i].colors,x.pieTes[i].value]);
}
alert(arr);
//输出Sony,7,Samsung,14,LG,21,Vizio,34,Insignia,24
alert不会以数组形式显示,实际结果应该如图所示console.log(arr);
⑥ java怎么将json对象转换成json数组
1、需要json的相关jar包
2、设置json格式字符串:
String str="{\"student\":[{\"name\":\"leilei\",\"age\":23},{\"name\":\"leilei02\",\"age\":23}]}";
3、建立相应的类:
public class StudentList {
List<Student> student;
public List<Student> getStudent() {
return student;
}
public void setStudent(List<Student> student) {
this.student = student;
}
}
public class Student {
private String name;
private int age;
//private StudentClass studentClass;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
4、测试程序
import java.util.List;
import org.codehaus.jackson.map.ObjectMapper;
⑦ java中把json怎么转换成数组
使用原生的解析:
String json = "...";
//遍历数组里的值,得到每个独立的对象,然后获取对应的值设置到声明好的对象中,最终创建对象完成后添加到集合中,如我自己代码里的片段:
for (int j = 0; j < array.length(); j++) {
obj = array.getJSONObject(j);
Data data = new Data();
mDataList.add(data);
}
数组声明
在数组的声明格式里,“数据类型”是声明数组元素的数据类型,可以是java语言中任意的数据类型,包括简单类型和结构类型。“数组名”是用来统一这些相同数据类型的名称,其命名规则和变量的命名规则相同。
数组声明之后,接下来便是要分配数组所需要的内存,这时必须用运算符new,其中“个数”是告诉编译器,所声明的数组要存放多少个元素,所以new运算符是通知编译器根据括号里的个数,在内存中分配一块空间供该数组使用。利用new运算符为数组元素分配内存空间的方式称为动态分配方式。
以上内容参考:网络-数组
⑧ 怎么把json数组转为字符串数组
将json字符串转成Java的Array数组
private String json = "{\"address\":\"chian\",\"birthday\":{\"birthday\":\"2010-11-22\"},"+
"\"email\":\"[email protected]\",\"id\":22,\"name\":\"tom\"}";
@Test
public void readJSON2Array() {
try {
json = "[" + json + "]";
jsonArray = JSONArray.fromObject(json);
Object[] os = jsonArray.toArray();
System.out.println(os.length);
Student[] stus = (Student[]) JSONArray.toArray(jsonArray, Student.class);
System.out.println(stus.length);
System.out.println(stus[0]);
} catch (Exception e) {
e.printStackTrace();
}
}
运行的结果如下:
==============JSON Arry String >>> Java Array ==================
#%%%{"address":"chian","birthday":{"birthday":"2010-11-22"},"email":"[email protected]","id":22,"name":"tom"}
1
{"address":"chian","birthday":{"birthday":"2010-11-22"},"email":"[email protected]","id":22,"name":"tom"}
{"address":"chian","birthday":{"birthday":"2010-11-22"},"email":"[email protected]","id":22,"name":"tom"}
1
将JSON字符串转成Java的List集合
private String json = "{\"address\":\"chian\",\"birthday\":{\"birthday\":\"2010-11-22\"},"+
"\"email\":\"[email protected]\",\"id\":22,\"name\":\"tom\"}";
public void readJSON2List() {
try {
json = "[" + json + "]";
jsonArray = JSONArray.fromObject(json);
List<Student> list = JSONArray.toList(jsonArray, Student.class);
System.out.println(list.size());
System.out.println(list.get(0));
list = JSONArray.toList(jsonArray);
System.out.println(list.size());
System.out.println(list.get(0));
} catch (Exception e) {
e.printStackTrace();
}
}
⑨ json数组怎么转成 string 数组 java
json有自己的方法
String str="";
JSONArray json = JSONArray.fromObject(str);
先转成string,在添加集合。
⑩ 怎样将json对象数组转换为字符串数组
将json字符串转成Java的Array数组
private String json = "{\"address\":\"chian\",\"birthday\":{\"birthday\":\"2010-11-22\"},"+
"\"email\":\"[email protected]\",\"id\":22,\"name\":\"tom\"}";
@Test
public void readJSON2Array() {
try {
json = "[" + json + "]";
jsonArray = JSONArray.fromObject(json);
Object[] os = jsonArray.toArray();
System.out.println(os.length);
Student[] stus = (Student[]) JSONArray.toArray(jsonArray, Student.class);
System.out.println(stus.length);
System.out.println(stus[0]);
} catch (Exception e) {
e.printStackTrace();
}
}
运行的结果如下:
==============JSON Arry String >>> Java Array ==================
#%%%{"address":"chian","birthday":{"birthday":"2010-11-22"},"email":"[email protected]","id":22,"name":"tom"}
1
{"address":"chian","birthday":{"birthday":"2010-11-22"},"email":"[email protected]","id":22,"name":"tom"}
{"address":"chian","birthday":{"birthday":"2010-11-22"},"email":"[email protected]","id":22,"name":"tom"}
1
将JSON字符串转成Java的List集合
private String json = "{\"address\":\"chian\",\"birthday\":{\"birthday\":\"2010-11-22\"},"+
"\"email\":\"[email protected]\",\"id\":22,\"name\":\"tom\"}";
public void readJSON2List() {
try {
json = "[" + json + "]";
jsonArray = JSONArray.fromObject(json);
List<Student> list = JSONArray.toList(jsonArray, Student.class);
System.out.println(list.size());
System.out.println(list.get(0));
list = JSONArray.toList(jsonArray);
System.out.println(list.size());
System.out.println(list.get(0));
} catch (Exception e) {
e.printStackTrace();
}
}