導航:首頁 > 源碼編譯 > md5演算法c語言實現

md5演算法c語言實現

發布時間:2022-07-26 00:11:53

⑴ c語言實現MD5加密演算法,出現問題求解

找不到md5.h的頭文件 將你的md5.h頭文件跟你的c文件放在同一目錄下

⑵ C語言實現文件傳輸時用md5加密

搜一下:C語言實現文件傳輸時用md5加密

⑶ 跪求大蝦幫忙實現下MD5的演算法(用C語言),剛找到工作,忘大家幫個忙,謝謝啊!

#include <stdio.h>
#include <stdlib.h>
#include <memory.h>
#include <time.h>
#include <errno.h>
#include <string.h>
#include <sys/socket.h>
#include <sys/types.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <netdb.h>
#include "../md5/md5.h"

#define T1 0xd76aa478
#define T2 0xe8c7b756
#define T3 0x242070db
#define T4 0xc1bdceee
#define T5 0xf57c0faf
#define T6 0x4787c62a
#define T7 0xa8304613
#define T8 0xfd469501
#define T9 0x698098d8
#define T10 0x8b44f7af
#define T11 0xffff5bb1
#define T12 0x895cd7be
#define T13 0x6b901122
#define T14 0xfd987193
#define T15 0xa679438e
#define T16 0x49b40821
#define T17 0xf61e2562
#define T18 0xc040b340
#define T19 0x265e5a51
#define T20 0xe9b6c7aa
#define T21 0xd62f105d
#define T22 0x02441453
#define T23 0xd8a1e681
#define T24 0xe7d3fbc8
#define T25 0x21e1cde6
#define T26 0xc33707d6
#define T27 0xf4d50d87
#define T28 0x455a14ed
#define T29 0xa9e3e905
#define T30 0xfcefa3f8
#define T31 0x676f02d9
#define T32 0x8d2a4c8a
#define T33 0xfffa3942
#define T34 0x8771f681
#define T35 0x6d9d6122
#define T36 0xfde5380c
#define T37 0xa4beea44
#define T38 0x4bdecfa9
#define T39 0xf6bb4b60
#define T40 0xbebfbc70
#define T41 0x289b7ec6
#define T42 0xeaa127fa
#define T43 0xd4ef3085
#define T44 0x04881d05
#define T45 0xd9d4d039
#define T46 0xe6db99e5
#define T47 0x1fa27cf8
#define T48 0xc4ac5665
#define T49 0xf4292244
#define T50 0x432aff97
#define T51 0xab9423a7
#define T52 0xfc93a039
#define T53 0x655b59c3

#define T54 0x8f0ccc92
#define T55 0xffeff47d
#define T56 0x85845dd1
#define T57 0x6fa87e4f
#define T58 0xfe2ce6e0
#define T59 0xa3014314
#define T60 0x4e0811a1
#define T61 0xf7537e82
#define T62 0xbd3af235
#define T63 0x2ad7d2bb
#define T64 0xeb86d391

static void md5_process(md5_state_t *pms, const md5_byte_t *data /*[64]*/)
{
md5_word_t
a = pms->abcd[0], b = pms->abcd[1],
c = pms->abcd[2], d = pms->abcd[3];
md5_word_t t;

#ifndef ARCH_IS_BIG_ENDIAN
# define ARCH_IS_BIG_ENDIAN 1 /* slower, default implementation */
#endif
#if ARCH_IS_BIG_ENDIAN

/*
* On big-endian machines, we must arrange the bytes in the right
* order. (This also works on machines of unknown byte order.)
*/
md5_word_t X[16];
const md5_byte_t *xp = data;
int i;

for (i = 0; i < 16; i, xp = 4)
X[i] = xp[0] (xp[1] << 8) (xp[2] << 16) (xp[3] << 24);

#else /* !ARCH_IS_BIG_ENDIAN */

/*
* On little-endian machines, we can process properly aligned data
* without ing it.
*/
md5_word_t xbuf[16];
const md5_word_t *X;

if (!((data - (const md5_byte_t *)0) & 3)) {
/* data are properly aligned */
X = (const md5_word_t *)data;
} else {
/* not aligned */
memcpy(xbuf, data, 64);
X = xbuf;
}
#endif

#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32 - (n))))

/* Round 1. */
/* Let [abcd k s i] denote the operation
a = b ((a F(b,c,d) X[k] T[i]) <<< s). */
#define F(x, y, z) (((x) & (y)) | (~(x) & (z)))
#define SET(a, b, c, d, k, s, Ti)\
t = a F(b,c,d) X[k] Ti;\
a = ROTATE_LEFT(t, s) b
/* Do the following 16 operations. */
SET(a, b, c, d, 0, 7, T1);
SET(d, a, b, c, 1, 12, T2);
SET(c, d, a, b, 2, 17, T3);
SET(b, c, d, a, 3, 22, T4);
SET(a, b, c, d, 4, 7, T5);
SET(d, a, b, c, 5, 12, T6);
SET(c, d, a, b, 6, 17, T7);

SET(b, c, d, a, 7, 22, T8);
SET(a, b, c, d, 8, 7, T9);
SET(d, a, b, c, 9, 12, T10);
SET(c, d, a, b, 10, 17, T11);
SET(b, c, d, a, 11, 22, T12);
SET(a, b, c, d, 12, 7, T13);
SET(d, a, b, c, 13, 12, T14);
SET(c, d, a, b, 14, 17, T15);
SET(b, c, d, a, 15, 22, T16);
#undef SET

/* Round 2. */
/* Let [abcd k s i] denote the operation
a = b ((a G(b,c,d) X[k] T[i]) <<< s). */
#define G(x, y, z) (((x) & (z)) | ((y) & ~(z)))
#define SET(a, b, c, d, k, s, Ti)\
t = a G(b,c,d) X[k] Ti;\
a = ROTATE_LEFT(t, s) b
/* Do the following 16 operations. */
SET(a, b, c, d, 1, 5, T17);
SET(d, a, b, c, 6, 9, T18);
SET(c, d, a, b, 11, 14, T19);
SET(b, c, d, a, 0, 20, T20);
SET(a, b, c, d, 5, 5, T21);
SET(d, a, b, c, 10, 9, T22);
SET(c, d, a, b, 15, 14, T23);
SET(b, c, d, a, 4, 20, T24);
SET(a, b, c, d, 9, 5, T25);
SET(d, a, b, c, 14, 9, T26);
SET(c, d, a, b, 3, 14, T27);
SET(b, c, d, a, 8, 20, T28);
SET(a, b, c, d, 13, 5, T29);
SET(d, a, b, c, 2, 9, T30);
SET(c, d, a, b, 7, 14, T31);
SET(b, c, d, a, 12, 20, T32);
#undef SET

⑷ 求生成MD5碼的c或c++代碼

自己用C語言寫的簡單的MD5演算法實現。

#include <stdio.h>
#include <stdlib.h>
#include <memory.h>
#include <math.h>

typedef unsigned char BYTE;
typedef unsigned int UINT;
typedef UINT MD5_SUB_ARRAY[16];
typedef UINT MD5_TRANSORM_FUNC(UINT,UINT,UINT);
typedef struct
{
UINT a;
UINT b;
UINT c;
UINT d;
MD5_SUB_ARRAY sub_array;
}MD5_TRANSFORM_PARAM;

const double MAX_INT = (double)0xFFFFFFFF + 1.0;

const UINT MD5_TRANSFORM_MATRIX[4][16][3] =
{

{
{ 0, 7, 1}, { 1,12, 2}, { 2,17, 3}, { 3,22, 4},
{ 4, 7, 5}, { 5,12, 6}, { 6,17, 7}, { 7,22, 8},
{ 8, 7, 9}, { 9,12,10}, {10,17,11}, {11,22,12},
{12, 7,13}, {13,12,14}, {14,17,15}, {15,22,16},
},

{
{ 1, 5,17}, { 6, 9,18}, {11,14,19}, { 0,20,20},
{ 5, 5,21}, {10, 9,22}, {15,14,23}, { 4,20,24},
{ 9, 5,25}, {14, 9,26}, { 3,14,27}, { 8,20,28},
{13, 5,29}, { 2, 9,30}, { 7,14,31}, {12,20,32},
},

{
{5, 4, 33}, { 8,11,34}, {11,16,35},{14, 23,36},
{1, 4, 37}, { 4,11,38}, { 7,16,39},{10, 23,40},
{13,4, 41}, { 0,11,42}, { 3,16,43},{ 6, 23,44},
{9, 4, 45}, {12,11,46}, {15,16,47},{ 2, 23,48},
},

{
{ 0,6,49}, { 7,10,50}, {14,15,51},{ 5, 21,52},
{12,6,53}, { 3,10,54}, {10,15,55},{ 1, 21,56},
{ 8,6,57}, {15,10,58}, { 6,15,59},{13, 21,60},
{ 4,6,61}, {11,10,62}, { 2,15,63},{ 9, 21,64},
},
};

static UINT MD5_TRANSFORM_ARRAY[65];

void MD5_Init()
{
int x;
for(x = 1; x <= 64; x++)
{
MD5_TRANSFORM_ARRAY[x] = (UINT)(MAX_INT * fabs(sin(x)));
}
}

UINT F(UINT x,UINT y,UINT z)
{
return ((x & y) | ((~x) & z));
}

UINT G(UINT x,UINT y,UINT z)
{
return ((x & z) | (y & (~z)));
}

UINT H(UINT x,UINT y,UINT z)
{
return (x ^ y ^ z);
}

UINT I(UINT x,UINT y,UINT z)
{
return (y ^ (x | (~z)));
}

BYTE* MD5_prepare_data(const BYTE* data,int len,int* new_len)
{
int rest,fill,size;
BYTE* new_data;
UINT bit_len;

// (1) 位元組補齊
rest = len % 56;
if (rest <= 56) fill = 56 - rest;
else fill = (64 - rest) + 56;

new_data = (BYTE*)malloc(len + fill + 8);
if (NULL == new_data) return NULL;

if (len > 0) memcpy(new_data,data,len);
if (fill > 0) memset(new_data + len,0x80,1);
if (fill > 1) memset(new_data + len + 1,0,fill - 1);

size = fill + len;

// (2) 附加數據的比特長度
bit_len = len * 8;
// (64位二進制數表示的)比特長度的低32位
memset(new_data + size + 0,(bit_len & 0x000000FF), 1);
memset(new_data + size + 1,(bit_len & 0x0000FF00) >> 8, 1);
memset(new_data + size + 2,(bit_len & 0x00FF0000) >> 16,1);
memset(new_data + size + 3,(bit_len & 0xFF000000) >> 24,1);
// 不考慮比特長度超出32位無符號數表示範圍,所以高32位總是0
memset(new_data + size + 4,0,4);

*new_len = size + 8;

return new_data;
}

void MD5_transform(MD5_TRANSFORM_PARAM* param,int ring,MD5_TRANSORM_FUNC func)
{
UINT a,b,c,d,s,k,i;
UINT abcd[4];
UINT *X,*T;
int index;

abcd[0] = param->a;
abcd[1] = param->b;
abcd[2] = param->c;
abcd[3] = param->d;
X = param->sub_array;
T = MD5_TRANSFORM_ARRAY;

for(index = 0; index < 16; index++)
{
a = abcd[(3 * index + 0) % 4];
b = abcd[(3 * index + 1) % 4];
c = abcd[(3 * index + 2) % 4];
d = abcd[(3 * index + 3) % 4];

k = MD5_TRANSFORM_MATRIX[ring][index][0];
s = MD5_TRANSFORM_MATRIX[ring][index][1];
i = MD5_TRANSFORM_MATRIX[ring][index][2];

a = a + func(b,c,d) + X[k] + T[i];
a = ( a << s) | ( a >> (32 - s)); // 循環左移
a = a + b;

abcd[(3 * index + 0) % 4] = a;
}

param->a = abcd[0];
param->b = abcd[1];
param->c = abcd[2];
param->d = abcd[3];
}

int MD5(const BYTE* data,int len)
{
int x,y,new_len;
MD5_TRANSFORM_PARAM param;
UINT AA,BB,CC,DD;
BYTE* buf;

MD5_Init();

buf = MD5_prepare_data(data,len,&new_len);
if (buf == NULL) return -1;

AA = 0x67452301;
BB = 0xefcdab89;
CC = 0x98badcfe;
DD = 0x10325476;

for(x = 0; x < new_len / 64; x++)
{
param.a = AA;
param.b = BB;
param.c = CC;
param.d = DD;

for(y = 0; y < 16; y++)
{
param.sub_array[y] = buf[64 * x + 4 * y + 0];
param.sub_array[y] += buf[64 * x + 4 * y + 1] << 8;
param.sub_array[y] += buf[64 * x + 4 * y + 2] << 16;
param.sub_array[y] += buf[64 * x + 4 * y + 3] << 24;
}
MD5_transform(¶m,0,F);
MD5_transform(¶m,1,G);
MD5_transform(¶m,2,H);
MD5_transform(¶m,3,I);

AA += param.a;
BB += param.b;
CC += param.c;
DD += param.d;
}

printf("MD5(\"%s\")=",data);

printf("%02X%02X%02X%02X",
(AA & 0x000000FF),
(AA & 0x0000FF00) >> 8,
(AA & 0x00FF0000) >> 16,
(AA & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(BB & 0x000000FF),
(BB & 0x0000FF00) >> 8,
(BB & 0x00FF0000) >> 16,
(BB & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(CC & 0x000000FF),
(CC & 0x0000FF00) >> 8,
(CC & 0x00FF0000) >> 16,
(CC & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(DD & 0x000000FF),
(DD & 0x0000FF00) >> 8,
(DD & 0x00FF0000) >> 16,
(DD & 0xFF000000) >> 24);

printf("\n");

return 0;
}

int main()
{
MD5("",0);
MD5("a",1);
MD5("abc",3);
MD5("message digest",14);
MD5("abcdefghijklmnopqrstuvwxyz",26);

return 0;
}

⑸ 求MD5加密演算法的C語言源碼

(轉載) #include <stdio.h> #include <stdlib.h> #include <memory.h> #include <time.h> #include <errno.h> #include <string.h> #include <sys/socket.h> #include <sys/types.h> #include <netinet/in.h> #include <arpa/inet.h> #include <netdb.h> #include "../md5/md5.h" #define T1 0xd76aa478 #define T2 0xe8c7b756 #define T3 0x242070db #define T4 0xc1bdceee #define T5 0xf57c0faf #define T6 0x4787c62a #define T7 0xa8304613 #define T8 0xfd469501 #define T9 0x698098d8 #define T10 0x8b44f7af #define T11 0xffff5bb1 #define T12 0x895cd7be #define T13 0x6b901122 #define T14 0xfd987193 #define T15 0xa679438e #define T16 0x49b40821 #define T17 0xf61e2562 #define T18 0xc040b340 #define T19 0x265e5a51 #define T20 0xe9b6c7aa #define T21 0xd62f105d #define T22 0x02441453 #define T23 0xd8a1e681 #define T24 0xe7d3fbc8 #define T25 0x21e1cde6 #define T26 0xc33707d6 #define T27 0xf4d50d87 #define T28 0x455a14ed #define T29 0xa9e3e905 #define T30 0xfcefa3f8 #define T31 0x676f02d9 #define T32 0x8d2a4c8a #define T33 0xfffa3942 #define T34 0x8771f681 #define T35 0x6d9d6122 #define T36 0xfde5380c #define T37 0xa4beea44 #define T38 0x4bdecfa9 #define T39 0xf6bb4b60 #define T40 0xbebfbc70 #define T41 0x289b7ec6 #define T42 0xeaa127fa #define T43 0xd4ef3085 #define T44 0x04881d05 #define T45 0xd9d4d039 #define T46 0xe6db99e5 #define T47 0x1fa27cf8 #define T48 0xc4ac5665 #define T49 0xf4292244 #define T50 0x432aff97 #define T51 0xab9423a7 #define T52 0xfc93a039 #define T53 0x655b59c3 #define T54 0x8f0ccc92 #define T55 0xffeff47d #define T56 0x85845dd1 #define T57 0x6fa87e4f #define T58 0xfe2ce6e0 #define T59 0xa3014314 #define T60 0x4e0811a1 #define T61 0xf7537e82 #define T62 0xbd3af235 #define T63 0x2ad7d2bb #define T64 0xeb86d391 static void md5_process(md5_state_t *pms, const md5_byte_t *data /*[64]*/) { md5_word_t a = pms->abcd[0], b = pms->abcd[1], c = pms->abcd[2], d = pms->abcd[3]; md5_word_t t; #ifndef ARCH_IS_BIG_ENDIAN # define ARCH_IS_BIG_ENDIAN 1 /* slower, default implementation */ #endif #if ARCH_IS_BIG_ENDIAN /* * On big-endian machines, we must arrange the bytes in the right * order. (This also works on machines of unknown byte order.) */ md5_word_t X[16]; const md5_byte_t *xp = data; int i; for (i = 0; i < 16; i, xp = 4) X[i] = xp[0] (xp[1] << 8) (xp[2] << 16) (xp[3] << 24); #else /* !ARCH_IS_BIG_ENDIAN */ /* * On little-endian machines, we can process properly aligned data * without ing it. */ md5_word_t xbuf[16]; const md5_word_t *X; if (!((data - (const md5_byte_t *)0) & 3)) { /* data are properly aligned */ X = (const md5_word_t *)data; } else { /* not aligned */ memcpy(xbuf, data, 64); X = xbuf; } #endif #define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32 - (n)))) /* Round 1. */ /* Let [abcd k s i] denote the operation a = b ((a F(b,c,d) X[k] T[i]) <<< s). */ #define F(x, y, z) (((x) & (y)) | (~(x) & (z))) #define SET(a, b, c, d, k, s, Ti)\ t = a F(b,c,d) X[k] Ti;\ a = ROTATE_LEFT(t, s) b /* Do the following 16 operations. */ SET(a, b, c, d, 0, 7, T1); SET(d, a, b, c, 1, 12, T2); SET(c, d, a, b, 2, 17, T3); SET(b, c, d, a, 3, 22, T4); SET(a, b, c, d, 4, 7, T5); SET(d, a, b, c, 5, 12, T6); SET(c, d, a, b, 6, 17, T7); SET(b, c, d, a, 7, 22, T8); SET(a, b, c, d, 8, 7, T9); SET(d, a, b, c, 9, 12, T10); SET(c, d, a, b, 10, 17, T11); SET(b, c, d, a, 11, 22, T12); SET(a, b, c, d, 12, 7, T13); SET(d, a, b, c, 13, 12, T14); SET(c, d, a, b, 14, 17, T15); SET(b, c, d, a, 15, 22, T16); #undef SET /* Round 2. */ /* Let [abcd k s i] denote the operation a = b ((a G(b,c,d) X[k] T[i]) <<< s). */ #define G(x, y, z) (((x) & (z)) | ((y) & ~(z))) #define SET(a, b, c, d, k, s, Ti)\ t = a G(b,c,d) X[k] Ti;\ a = ROTATE_LEFT(t, s) b /* Do the following 16 operations. */ SET(a, b, c, d, 1, 5, T17); SET(d, a, b, c, 6, 9, T18); SET(c, d, a, b, 11, 14, T19); SET(b, c, d, a, 0, 20, T20); SET(a, b, c, d, 5, 5, T21); SET(d, a, b, c, 10, 9, T22); SET(c, d, a, b, 15, 14, T23); SET(b, c, d, a, 4, 20, T24); SET(a, b, c, d, 9, 5, T25); SET(d, a, b, c, 14, 9, T26); SET(c, d, a, b, 3, 14, T27); SET(b, c, d, a, 8, 20, T28); SET(a, b, c, d, 13, 5, T29); SET(d, a, b, c, 2, 9, T30); SET(c, d, a, b, 7, 14, T31); SET(b, c, d, a, 12, 20, T32); #undef SET

⑹ 求一個簡單的md5加密程序C或C++代碼

C語言實現MD5演算法
#include<stdio.h>

#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define RL(x, y) (((x) << (y)) | ((x) >> (32 - (y)))) //x向左循環移y位

#define PP(x) (x<<24)|((x<<8)&0xff0000)|((x>>8)&0xff00)|(x>>24) //將x高低位互換,例如PP(aabbccdd)=ddccbbaa

#define FF(a, b, c, d, x, s, ac) a = b + (RL((a + F(b,c,d) + x + ac),s))
#define GG(a, b, c, d, x, s, ac) a = b + (RL((a + G(b,c,d) + x + ac),s))
#define HH(a, b, c, d, x, s, ac) a = b + (RL((a + H(b,c,d) + x + ac),s))
#define II(a, b, c, d, x, s, ac) a = b + (RL((a + I(b,c,d) + x + ac),s))

unsigned A,B,C,D,a,b,c,d,i,len,flen[2],x[16]; //i臨時變數,len文件長,flen[2]為64位二進製表示的文件初始長度
char filename[200]; //文件名
FILE *fp;

void md5(){ //MD5核心演算法,供64輪

a=A,b=B,c=C,d=D;
/**//* Round 1 */
FF (a, b, c, d, x[ 0], 7, 0xd76aa478); /**//* 1 */
FF (d, a, b, c, x[ 1], 12, 0xe8c7b756); /**//* 2 */
FF (c, d, a, b, x[ 2], 17, 0x242070db); /**//* 3 */
FF (b, c, d, a, x[ 3], 22, 0xc1bdceee); /**//* 4 */
FF (a, b, c, d, x[ 4], 7, 0xf57c0faf); /**//* 5 */
FF (d, a, b, c, x[ 5], 12, 0x4787c62a); /**//* 6 */
FF (c, d, a, b, x[ 6], 17, 0xa8304613); /**//* 7 */
FF (b, c, d, a, x[ 7], 22, 0xfd469501); /**//* 8 */
FF (a, b, c, d, x[ 8], 7, 0x698098d8); /**//* 9 */
FF (d, a, b, c, x[ 9], 12, 0x8b44f7af); /**//* 10 */
FF (c, d, a, b, x[10], 17, 0xffff5bb1); /**//* 11 */
FF (b, c, d, a, x[11], 22, 0x895cd7be); /**//* 12 */
FF (a, b, c, d, x[12], 7, 0x6b901122); /**//* 13 */
FF (d, a, b, c, x[13], 12, 0xfd987193); /**//* 14 */
FF (c, d, a, b, x[14], 17, 0xa679438e); /**//* 15 */
FF (b, c, d, a, x[15], 22, 0x49b40821); /**//* 16 */

/**//* Round 2 */
GG (a, b, c, d, x[ 1], 5, 0xf61e2562); /**//* 17 */
GG (d, a, b, c, x[ 6], 9, 0xc040b340); /**//* 18 */
GG (c, d, a, b, x[11], 14, 0x265e5a51); /**//* 19 */
GG (b, c, d, a, x[ 0], 20, 0xe9b6c7aa); /**//* 20 */
GG (a, b, c, d, x[ 5], 5, 0xd62f105d); /**//* 21 */
GG (d, a, b, c, x[10], 9, 0x02441453); /**//* 22 */
GG (c, d, a, b, x[15], 14, 0xd8a1e681); /**//* 23 */
GG (b, c, d, a, x[ 4], 20, 0xe7d3fbc8); /**//* 24 */
GG (a, b, c, d, x[ 9], 5, 0x21e1cde6); /**//* 25 */
GG (d, a, b, c, x[14], 9, 0xc33707d6); /**//* 26 */
GG (c, d, a, b, x[ 3], 14, 0xf4d50d87); /**//* 27 */
GG (b, c, d, a, x[ 8], 20, 0x455a14ed); /**//* 28 */
GG (a, b, c, d, x[13], 5, 0xa9e3e905); /**//* 29 */
GG (d, a, b, c, x[ 2], 9, 0xfcefa3f8); /**//* 30 */
GG (c, d, a, b, x[ 7], 14, 0x676f02d9); /**//* 31 */
GG (b, c, d, a, x[12], 20, 0x8d2a4c8a); /**//* 32 */

/**//* Round 3 */
HH (a, b, c, d, x[ 5], 4, 0xfffa3942); /**//* 33 */
HH (d, a, b, c, x[ 8], 11, 0x8771f681); /**//* 34 */
HH (c, d, a, b, x[11], 16, 0x6d9d6122); /**//* 35 */
HH (b, c, d, a, x[14], 23, 0xfde5380c); /**//* 36 */
HH (a, b, c, d, x[ 1], 4, 0xa4beea44); /**//* 37 */
HH (d, a, b, c, x[ 4], 11, 0x4bdecfa9); /**//* 38 */
HH (c, d, a, b, x[ 7], 16, 0xf6bb4b60); /**//* 39 */
HH (b, c, d, a, x[10], 23, 0xbebfbc70); /**//* 40 */
HH (a, b, c, d, x[13], 4, 0x289b7ec6); /**//* 41 */
HH (d, a, b, c, x[ 0], 11, 0xeaa127fa); /**//* 42 */
HH (c, d, a, b, x[ 3], 16, 0xd4ef3085); /**//* 43 */
HH (b, c, d, a, x[ 6], 23, 0x04881d05); /**//* 44 */
HH (a, b, c, d, x[ 9], 4, 0xd9d4d039); /**//* 45 */
HH (d, a, b, c, x[12], 11, 0xe6db99e5); /**//* 46 */
HH (c, d, a, b, x[15], 16, 0x1fa27cf8); /**//* 47 */
HH (b, c, d, a, x[ 2], 23, 0xc4ac5665); /**//* 48 */

/**//* Round 4 */
II (a, b, c, d, x[ 0], 6, 0xf4292244); /**//* 49 */
II (d, a, b, c, x[ 7], 10, 0x432aff97); /**//* 50 */
II (c, d, a, b, x[14], 15, 0xab9423a7); /**//* 51 */
II (b, c, d, a, x[ 5], 21, 0xfc93a039); /**//* 52 */
II (a, b, c, d, x[12], 6, 0x655b59c3); /**//* 53 */
II (d, a, b, c, x[ 3], 10, 0x8f0ccc92); /**//* 54 */
II (c, d, a, b, x[10], 15, 0xffeff47d); /**//* 55 */
II (b, c, d, a, x[ 1], 21, 0x85845dd1); /**//* 56 */
II (a, b, c, d, x[ 8], 6, 0x6fa87e4f); /**//* 57 */
II (d, a, b, c, x[15], 10, 0xfe2ce6e0); /**//* 58 */
II (c, d, a, b, x[ 6], 15, 0xa3014314); /**//* 59 */
II (b, c, d, a, x[13], 21, 0x4e0811a1); /**//* 60 */
II (a, b, c, d, x[ 4], 6, 0xf7537e82); /**//* 61 */
II (d, a, b, c, x[11], 10, 0xbd3af235); /**//* 62 */
II (c, d, a, b, x[ 2], 15, 0x2ad7d2bb); /**//* 63 */
II (b, c, d, a, x[ 9], 21, 0xeb86d391); /**//* 64 */

A += a;
B += b;
C += c;
D += d;

}

main(){
while(1){
printf("Input file:");
gets(filename); //用get函數,避免scanf以空格分割數據,
if (filename[0]==34) filename[strlen(filename)-1]=0,strcpy(filename,filename+1); //支持文件拖曳,但會多出雙引號,這里是處理多餘的雙引號
if (!strcmp(filename,"exit")) exit(0); //輸入exit退出
if (!(fp=fopen(filename,"rb"))) {printf("Can not open this file!\n");continue;} //以二進制打開文件
fseek(fp, 0, SEEK_END); //文件指針轉到文件末尾
if((len=ftell(fp))==-1) {printf("Sorry! Can not calculate files which larger than 2 GB!\n");fclose(fp);continue;} //ftell函數返回long,最大為2GB,超出返回-1
rewind(fp); //文件指針復位到文件頭
A=0x67452301,B=0xefcdab89,C=0x98badcfe,D=0x10325476; //初始化鏈接變數
flen[1]=len/0x20000000; //flen單位是bit
flen[0]=(len%0x20000000)*8;
memset(x,0,64); //初始化x數組為0
fread(&x,4,16,fp); //以4位元組為一組,讀取16組數據
for(i=0;i<len/64;i++){ //循環運算直至文件結束
md5();
memset(x,0,64);
fread(&x,4,16,fp);
}
((char*)x)[len%64]=128; //文件結束補1,補0操作,128二進制即10000000
if(len%64>55) md5(),memset(x,0,64);
memcpy(x+14,flen,8); //文件末尾加入原文件的bit長度
md5();
fclose(fp);
printf("MD5 Code:%08x%08x%08x%08x\n",PP(A),PP(B),PP(C),PP(D)); //高低位逆反輸出
}
}

⑺ C語言求文件MD5的函數用法

#ifndef MD5_H
#define MD5_H

typedef struct
{
unsigned int count[2];
unsigned int state[4];
unsigned char buffer[64];
}MD5_CTX;

#define F(x,y,z) ((x & y) | (~x & z))
#define G(x,y,z) ((x & z) | (y & ~z))
#define H(x,y,z) (x^y^z)
#define I(x,y,z) (y ^ (x | ~z))
#define ROTATE_LEFT(x,n) ((x << n) | (x >> (32-n)))
#define FF(a,b,c,d,x,s,ac) \
{ \
a += F(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define GG(a,b,c,d,x,s,ac) \
{ \
a += G(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define HH(a,b,c,d,x,s,ac) \
{ \
a += H(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define II(a,b,c,d,x,s,ac) \
{ \
a += I(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
void MD5Init(MD5_CTX *context);
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen);
void MD5Final(MD5_CTX *context,unsigned char digest[16]);
void MD5Transform(unsigned int state[4],unsigned char block[64]);
void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len);
void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len);

#endif

源文件md5.c

#include <memory.h>
#include "md5.h"

unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

void MD5Init(MD5_CTX *context)
{
context->count[0] = 0;
context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xEFCDAB89;
context->state[2] = 0x98BADCFE;
context->state[3] = 0x10325476;
}
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen)
{
unsigned int i = 0,index = 0,partlen = 0;
index = (context->count[0] >> 3) & 0x3F;
partlen = 64 - index;
context->count[0] += inputlen << 3;
if(context->count[0] < (inputlen << 3))
context->count[1]++;
context->count[1] += inputlen >> 29;

if(inputlen >= partlen)
{
memcpy(&context->buffer[index],input,partlen);
MD5Transform(context->state,context->buffer);
for(i = partlen;i+64 <= inputlen;i+=64)
MD5Transform(context->state,&input[i]);
index = 0;
}
else
{
i = 0;
}
memcpy(&context->buffer[index],&input[i],inputlen-i);
}
void MD5Final(MD5_CTX *context,unsigned char digest[16])
{
unsigned int index = 0,padlen = 0;
unsigned char bits[8];
index = (context->count[0] >> 3) & 0x3F;
padlen = (index < 56)?(56-index):(120-index);
MD5Encode(bits,context->count,8);
MD5Update(context,PADDING,padlen);
MD5Update(context,bits,8);
MD5Encode(digest,context->state,16);
}
void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len)
{
unsigned int i = 0,j = 0;
while(j < len)
{
output[j] = input[i] & 0xFF;
output[j+1] = (input[i] >> 8) & 0xFF;
output[j+2] = (input[i] >> 16) & 0xFF;
output[j+3] = (input[i] >> 24) & 0xFF;
i++;
j+=4;
}
}
void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len)
{
unsigned int i = 0,j = 0;
while(j < len)
{
output[i] = (input[j]) |
(input[j+1] << 8) |
(input[j+2] << 16) |
(input[j+3] << 24);
i++;
j+=4;
}
}
void MD5Transform(unsigned int state[4],unsigned char block[64])
{
unsigned int a = state[0];
unsigned int b = state[1];
unsigned int c = state[2];
unsigned int d = state[3];
unsigned int x[64];
MD5Decode(x,block,64);
FF(a, b, c, d, x[ 0], 7, 0xd76aa478); /* 1 */
FF(d, a, b, c, x[ 1], 12, 0xe8c7b756); /* 2 */
FF(c, d, a, b, x[ 2], 17, 0x242070db); /* 3 */
FF(b, c, d, a, x[ 3], 22, 0xc1bdceee); /* 4 */
FF(a, b, c, d, x[ 4], 7, 0xf57c0faf); /* 5 */
FF(d, a, b, c, x[ 5], 12, 0x4787c62a); /* 6 */
FF(c, d, a, b, x[ 6], 17, 0xa8304613); /* 7 */
FF(b, c, d, a, x[ 7], 22, 0xfd469501); /* 8 */
FF(a, b, c, d, x[ 8], 7, 0x698098d8); /* 9 */
FF(d, a, b, c, x[ 9], 12, 0x8b44f7af); /* 10 */
FF(c, d, a, b, x[10], 17, 0xffff5bb1); /* 11 */
FF(b, c, d, a, x[11], 22, 0x895cd7be); /* 12 */
FF(a, b, c, d, x[12], 7, 0x6b901122); /* 13 */
FF(d, a, b, c, x[13], 12, 0xfd987193); /* 14 */
FF(c, d, a, b, x[14], 17, 0xa679438e); /* 15 */
FF(b, c, d, a, x[15], 22, 0x49b40821); /* 16 */

閱讀全文

與md5演算法c語言實現相關的資料

熱點內容
多個jpg合成pdf 瀏覽:929
pdf轉word是圖片 瀏覽:939
程序員看不懂怎麼辦 瀏覽:271
linux操作系統題 瀏覽:765
單片機無符號數加法 瀏覽:227
應用隱藏加密怎麼關閉 瀏覽:269
汽車空調的壓縮機電線有什麼用 瀏覽:429
電腦加密圖片如何取消加密 瀏覽:340
慧凈電子51單片機視頻 瀏覽:343
javamap賦值 瀏覽:165
什麼app可以玩掌機游戲 瀏覽:46
java簡單聊天室 瀏覽:462
通用汽車編程軟體 瀏覽:432
一級抗震框架梁箍筋加密區規定是多少 瀏覽:974
教你如何把安卓手機變成蘋果 瀏覽:11
app編譯分類 瀏覽:323
怎麼用伺服器的資源包 瀏覽:199
oa軟體手機登陸伺服器地址 瀏覽:289
androidrtp打包 瀏覽:723
信息被加密碼了怎麼辦 瀏覽:420